Home Entrance Exam Prep Calendar Questions: Selected Aptitude Questions & Answers (MCQs)

Calendar Questions: Selected Aptitude Questions & Answers (MCQs)

Studying calendars helps us learn about leap years, odd days, and how to solve calendar questions in logical reasoning. Get ready to enhance your knowledge and find answers to your burning calendar questions right here.

Definition of Calendar

A calendar is a visual representation that displays the days, weeks, and months of a specific year, often providing details about different seasons as well.

Grasping the Basic Structure of a Calendar

  1. Ordinary Year: An ordinary year is defined as a year that contains 365 days. Examples of such years include 1879, 2009, and 2019.

  2. Leap Year: A leap year is defined as a year that consists of 366 days instead of the usual 365. Examples of leap years include 2012, 2016, and 2020.

  3. When you divide 365 by 7, the result is 52 with a remainder of 1, meaning that a typical year consists of 52 weeks plus one additional day. This extra day is commonly known as an “odd day” in discussions about calendars.

  4. A leap year consists of 366 days. When you divide 366 by 7, you get a quotient of 52 and a remainder of 2. This means that in a leap year, there are 52 full weeks along with 2 additional days. These extra days are commonly known as “odd days.”

    The table below shows the count of odd days for each month in a calendar year:

    Month Number of odd days
    January 3
    February(ordinary/leap) (0/1)
    March 3
    April 2
    May 3
    June 2
    July 3
    August 3
    September 2
    October 3
    November 2
    December 3

Understanding Days of the Week

The week starts on Monday, which is why Saturday and Sunday are known as the weekend. This understanding can help simplify calculations and save time during exams.

The table below illustrates the coding system for the days of the week:

Code of the day Day
0 Sunday
1 Monday
2 Tuesday
3 Wednesday
4 Thursday
5 Friday
6 Saturday

This table assists in interpreting the responses gathered after completing the problem-solving steps related to calendar subjects. For example, if the final result of your calculations is 10, you would divide that number by 7, since there are 7 days in a week.

The remainder from this division, which is 3, helps you identify the correct answer from the options provided. In this case, a remainder of 3 corresponds to Wednesday as the correct choice.

Understanding the Concept of Leap Year

A leap year is a year that has 366 days instead of the usual 365, with an extra day added to February (February 29). Leap years occur every 4 years to help synchronize the calendar year with the Earth's orbit around the Sun, which takes about 365.25 days.

Rules to determine a leap year:

  1. A year is a leap year if it is divisible by 4.

  2. However, if the year is divisible by 100, it is not a leap year unless:

  3. The year is also divisible by 400. In that case, it is a leap year.

Examples:

  • 2020 was a leap year (divisible by 4).

  • 1900 was not a leap year (divisible by 100 but not 400).

  • 2000 was a leap year (divisible by 400).

Concept of Odd Days in a Century

The concept of odd days in a century helps students answer the question of calendars as quickly as possible. Let us study the question below in order to understand the concept better:

What was the day of the week on December 31st in the year 100 A.D.?

Solution: Let's examine the initial century, specifically from Year 1 A.D. to Year 100 A.D.

When we divide 100 by 4, we find that within the first century, there are 76 ordinary years and 24 leap years. Although dividing 100 by 4 gives us 25, the year 100 is not a leap year because it is not divisible by 4. Therefore, we count only 24 leap years instead of 25.

100 years = 76 ordinary years + 24 leap years

An ordinary year contributes 1 odd day, while a leap year adds 2 odd days. Therefore, if we consider 76 ordinary years, they will accumulate a total of 76 odd days. In the case of 24 leap years, they will generate 24 multiplied by 2, resulting in 48 odd days. When we combine these two figures, we find that there are 124 odd days altogether.

100 years = (76 x 1 + 24 x 2) odd days = 124 odd days.

When you divide the total of 124 odd days by 7, you find that it equals 17 weeks with a remainder of 5. This means that in those 124 days, there are 17 complete weeks and an additional 5 odd days left over.

100 years = 17 weeks + 5 odd days. Therefore, the number of odd days in 100 years = 5.

According to the table provided above, the number 5 corresponds to Friday when decoding numbers into days of the week.

In the same way, you can determine the final day of another century years by applying this reasoning. Over a span of 100 years, there are typically 5 odd days. Therefore, for 200 years, we would expect to see 10 odd days. Since 10 exceeds 7, if we divide 10 by 7, the remainder is 3. This indicates that after 200 years, there are 3 odd days remaining. Consequently, this means that December 31, 2000, fell on a Wednesday.

Number of odd days in 200 years = (5 x 2) = 10 = (7+3) = 3 odd days.

In a century, there are 5 odd days, which means that over 200 years, there are a total of 10 odd days. Following this pattern, it stands to reason that in 300 years, there would be 15 odd days. When you divide 15 by 7, the remainder is 1, which tells us that the last day of the year 300 falls on a Monday. Therefore, the final day of that year was a Monday.

Number of odd days in 300 years = (5 x 3) = 15 = (14+1) = 1 odd day.

Over a span of 400 years, there should be a total of 20 odd days because the last year, being a leap year is divisible by 4. Therefore, this specific leap year adds one more odd day, resulting in 21 odd days altogether. When you divide 21 by 7, the remainder is zero. This means that after 400 years, there are no odd days left, indicating that the starting day was a Sunday.

The table below provides a logical approach to calculating the number of odd days and identifying the corresponding days of the week in 100 years:

Century Number of odd days Day of the week
100 5 Friday
200 3 Wednesday
300 1 Monday
400 0 Sunday
500 = (100+400) (5+0) = 5 Friday
600 =(200+400) (3+0) =3 Wednesday
700 = (300+400) (1+0) = 1 Monday
800 = (400+400) (0+0) = 0 Sunday
900 = ( 400 + 500) (0 + 5) = 5 Friday
1000 = (500 +500) (5+5)= (7+3) = 3 Wednesday

Studying the table closely, you will observe the following points:

1. Every four centuries, the sequence of days repeats itself, including the specific days on which events conclude. The recurring order of these days is always Friday, Wednesday, Monday, and Sunday.

2. A century will conclude on one of the following days: Friday, Wednesday, Monday, or Sunday. These days correspond to the values of 5, 3, 1, and 0 when decoded.

3. A century cannot conclude on a Tuesday, Thursday, or Saturday, as the numerical representations for these days are 2, 4, and 6, respectively.

Tips For Calendar Reasoning Questions

Let us look at some of the tips for solving calendar reasoning questions:

Understanding Concepts

To tackle calendar questions effectively, grasp the fundamentals like leap years and odd days.

Practice & Techniques

Regular practice with various types of calendar reasoning questions is essential for honing your skills. Employ logical reasoning techniques to break down the information systematically and reach accurate conclusions.

To improve your logical reasoning skills specifically for calendar questions, there is a dedicated platform that offers practice materials just for you. Click here to access the platform right away!

Top 10 Calendar Questions & Answers For Practice (MCQs)

Practice solving calendar questions to improve your grasp of calendar reasoning. By tackling a variety of sample problems, you can enhance your skills:

Question 1. January 1, 2006, was Sunday of the week. What day of the week was it on January 1, 2010?

a) Sunday

b) Monday

c) Tuesday

d) Friday

Solution: We need to find the day of the week for January 1, 2010, considering January 1, 2006, was a Sunday. There are 4 years between 2006 and 2010. Of these, only 2008 is a leap year.

In regular years, 3 out of 4 contribute 3×1-day shift (each year moves 1 day forward) = 3 days shift.

Leap year (1 out of 4) contributes 1×2 day shift (leap year moves 2 days forward) = 2 days shift.

Total day shift = 3 days (regular years) + 2 days (leap year) = 5 days shift.

Since it was Sunday on January 1, 2006 (starting point), moving forward by 5 days would result in:

Sunday (Starting Point) + 1 day = Monday

Monday + 1 day = Tuesday

Tuesday + 1 day = Wednesday

Wednesday + 1 day = Thursday

Thursday + 1 day = Friday

Friday will be the day of the week on January 1, 2010.

Question 2. December 8th, 2007, was Saturday. What day of the week was it on December 8th, 2006?

a) Sunday

b) Monday

c) Tuesday

d) Friday

Solution: We know that Saturday falls on December 8th, 2007.

When a regular year of 365 days is divided by 7 days a week, 1 odd is the result due to the remainder. So, in a regular year, the day of the week moves forward by 1 day compared to the previous year.

Since December 8th, 2007, was a Saturday, moving back one year (to December 8th, 2006) would result in the previous day of the week.

Therefore, Friday was the day of the week on December 8th, 2006.

Question 3. On February 8th, 2005, it was Tuesday. What day of the week was it on February 8th, 2004?

a) Tuesday

b) Monday

c) Sunday

d) Wednesday

Solution: We know it was Tuesday, February 8th, 2005. We need to find the day of the week for February 8th, 2004, considering 2004 is a leap year.

A regular year has 365 days and moves the day of the week forward by 1 day compared to the previous year.

A leap year has 366 days and moves the day of the week forward by 2 days compared to the previous year.

Since 2004 is a leap year, February 8th, 2004, will be 2 days behind February 8th, 2005, regarding the day of the week.

Question 4. Today is Monday. After 61 days, it will be

a) Monday
b) Tuesday
c) Wednesday
d) Saturday

Solution: Given that today is Monday, we start with this information. We are asked to determine the day of the week 61 days from today. To do this, we divide 61 by 7 to find out how many weeks there are and then take the remainder to determine the additional days beyond those weeks.

In this case, 61 divided by 7 equals 8 with a remainder of 5.

We add these 5 days (remainder) one by one to the current day, starting with Monday:

Monday + 1 day = Tuesday

Tuesday + 1 day = Wednesday

Wednesday + 1 day = Thursday

Thursday + 1 day = Friday

Friday + 1 day = Saturday

After adding 5 days to Monday, we find it will be Saturday. So, 61 days from today (Monday) will be Saturday.

Question 5. Sarah notices that her birthday falls on the same day of the week every year. If her birthday was on a Thursday this year, what day of the week would it be in five years?

a) Friday
b) Monday
c) Tuesday
d) Wednesday

Solution: Sarah's birthday is on a Thursday this year.

In the first year (next year), her birthday will be on Thursday + 1 day = Friday.

In the second year, her birthday will be on Friday + 1 day = Saturday.

In the third year, her birthday will be on Saturday + 1 day = Sunday.

In the fourth year (leap year), her birthday will be on Sunday + 2 days = Tuesday.

In the fifth year, her birthday will be on Tuesday + 1 day = Wednesday.

Therefore, in five years, Sarah's birthday will fall on a Wednesday.

Question 6. If May 1st of a certain year falls on a Friday, on what day of the week will December 25th of the same year fall?

a) Wednesday
b) Thursday
c) Friday
d) Saturday

Solution: May 1st of a certain year falls on a Friday. We need to find out what day of the week December 25th of the same year falls on. From May 1st to May 31st, there are 31 days. So, May 31st falls on a Sunday.

June, July, August, September, October, and November have 30, 31, 31, 30, 31, and 30 days, respectively. These months will follow a pattern where the last day of each month is the next day of the week after the last day of the previous month.

Therefore, December 1st will also fall on a Tuesday. December 1st to December 25th comprises 25 days.

Since December 1st is a Tuesday, December 8th will also be a Tuesday, December 15th will be a Tuesday, and December 22nd will be a Tuesday.

December 25th is three days after December 22nd.

Since December 22nd is a Tuesday and we add three more days, we land on Friday. Therefore, December 25th of the same year falls on a Friday.

Question 7. If September 10th of a certain year falls on a Tuesday, on what day of the week will March 20th of the following year fall?

a) Monday
b) Tuesday
c) Wednesday
d) Thursday

Solution: September 10th of a certain year falls on a Tuesday.

We need to find out what day of the week March 20th of the following year falls on.

From September 10th to September 30th, there are 20 days remaining in September.

October, November, and December have 31, 30, and 31 days respectively.

Counting the days and considering the number of days in each month, December 31st falls on a Tuesday.

January has 31 days.

February has 28 days in a non-leap year.

March has 20 days until March 20th.

Since December 31st is a Tuesday, January 7th will also be a Tuesday, and so on.

By counting weeks, March 19th will be a Tuesday, and March 20th will be a Wednesday, one day after March 19th. Therefore, March 20th of the following year falls on a Wednesday.

Question 8. If Neha's birthday falls on April 15th of a certain year, and it's a Saturday, on what day of the week will her birthday fall on November 10th of the same year?

a) Monday
b) Tuesday
c) Wednesday
d) Saturday

Solution: Neha's birthday falls on April 15th of a certain year, and it's a Saturday.

We need to find out what day of the week Neha's birthday will fall on, November 10th of the same year.

From April 15th to April 30th, there are 16 days remaining in April.

From May 1st to November 10th, there are:

May has 31 days,

June has 30 days,

July has 31 days,

August has 31 days,

September has 30 days, and

October has 31 days.

Counting the days in May through October totals 184 days.

Adding 16 days from April and 184 days from May through October, we have a total of 200 days.

Since 200 days is divisible by 7 (which represents a full week), November 10th falls exactly 28 full weeks after April 15th.

Since April 15th is a Saturday, adding 28 weeks brings us to another Saturday. Therefore, Neha's birthday on November 10th of the same year will also fall on a Saturday.

Question 9. If Riya's birthday falls on the 15th of February of a certain year and it's a Thursday, on what day of the week will her birthday fall on October 10th of the same year?

a) Monday
b) Tuesday
c) Wednesday
d) Thursday

Solution: Riya's birthday falls on the 15th of February of a certain year, a Thursday.

We need to find out what day of the week Riya's birthday will fall on, October 10th of the same year. From February 15th to the end of February, there are 13 days remaining in February.

From March to September, we have:

March: 31 days

April: 30 days

May: 31 days

June: 30 days

July: 31 days

August: 31 days

September: 30 days

Now, adding up the days from March to September, we have a total of 214 days.

Adding 13 days from February and 10 days from October, we have a total of 237.

237 divided by 7 gives a quotient of 33 and a remainder of 6.

This means that October 10th falls 33 weeks and 6 days after February 15th.

Since February 15th is a Thursday, adding 6 days to Thursday gives us Wednesday.

Therefore, Riya's birthday on October 10th of the same year will fall on a Wednesday.

Question 10. Neha is planning a trip that starts on the 15th of every month and lasts for 5 days. If she starts her trip on a Monday in January, what day of the week will she end her trip in November of the same year?

a) Monday
b) Tuesday
c) Wednesday
d) Thursday

Solution: Neha starts her trip on the 15th of every month, lasting 5 days. She starts her trip on a Monday in January. We need to find out what day of the week Neha will end her trip in November of the same year.

Neha starts her trip on Monday, January 15th. Each of Neha's trips lasts for 5 days so that she will end her trip on January 19th (Monday + 4 days).

From January to November, there are 10 months. Considering that each trip lasts 5 days, Neha would have completed 50 days of her trips by the end of October.

Since Neha's trips start on the 15th of every month, her trip in November would begin on November 15th.

Since 50 days is not divisible by 7, we need to find the remainder when 50 is divided by 7. The remainder is 1. Adding this remainder to the initial day (Monday) will give us the day of the week for the 50th day.

Therefore, Neha will end her trip in November of the same year on the day of the week that is 1 day ahead of Monday, which is Tuesday. 

Conclusion

The exploration of calendar questions has shed light on the intricate world of calendars, leap years, odd days, and effective strategies for solving related reasoning questions. By grasping these concepts and practicing sample questions, individuals can enhance their problem-solving skills and excel in this domain.

Engage in further practice, challenge yourself with diverse scenarios, and continue exploring the fascinating realm of calendars to sharpen your reasoning abilities.

Frequently Asked Questions (FAQs)

1. What are the basics of understanding calendars?

Understanding calendar basics encompasses learning about days, months, years, and their relationships. It involves comprehending concepts like weekdays, leap years, odd days, and different calendars used worldwide.

2. How do you evaluate leap years in a calendar?

Grasping the evaluation of leap years involves knowing that a leap year has 366 days instead of 365. It occurs every four years except for centuries, which are not divisible by 400. This adjustment compensates for the extra quarter day in Earth's orbit around the sun.

3. What are odd days in calendars, and how are they counted?

Odd days in calendars refer to the leftover days when a certain number of weeks or complete months don't fit into a given period. Counting odd days involves dividing the total number of days by seven (days in a week) and considering the remainder as odd days.

4. How can one effectively solve calendar reasoning questions?

Effective strategies for solving calendar reasoning questions include practicing regularly to improve mental calculations related to dates and weekdays. Understanding basic calendar concepts such as leap years and odd days is crucial for mastering reasoning questions efficiently.

5. Why is it important to explore various types of calendars used today?

Discovering various types of calendars used today helps broaden knowledge of cultural diversity and historical significance related to timekeeping systems globally. Exploring different calendars enhances understanding of traditions, religious practices, astronomical observations, and societal influences on time reckoning.

Suggested reads:

 

Kaihrii Thomas
Associate Content Writer

Instinctively, I fall for nature, music, humour, reading, writing, listening, travelling, observing, learning, unlearning, friendship, exercise, etc., all these from the cradle to the grave- that's ME! It's my irrefutable belief in the uniqueness of all. I'll vehemently defend your right to be your best while I expect the same from you!

TAGS
Placement UPSC GMAT Banking
Updated On: 25 Sep'24, 12:52 PM IST